python多线程最优线程数

• Ncpu=CPU的数量
• Ucpu=目标CPU使用率
• W/C=等待时间与计算时间的比率

为保持处理器达到期望的使用率，最优的线程池的大小等于

Nthreads=Ncpu?Ucpu?（1+W/C）

• cpu密集型任务，即$W<<C$，则$W/C≈0$，则$Nthreads=Ncpu*Ucpu$

如果希望CPU利用率为100%，则$Nthreads=Ncpu$

• IO密集型任务，即系统大部分时间在跟I/O交互，而这个时间线程不会占用CPU来处理，即在这个时间范围内，可以由其他线程来使用CPU，因而可以多配置一些线程。
• 混合型任务，二者都占有一定的时间

线城池

对于任务数量不断增加的程序，每有一个任务就生成一个线程，最终会导致线程数量的失控。对于任务数量不断增加的程序，固定线程数量的线程池是必要的。

方法一：使用threadpool模块

threadpool是一个比较老的模块了，支持py2 和 py3 。

import threadpool
import time

def sayhello (a):
    print("hello: "+a)
    time.sleep(2)

def main():
    global result
    seed=["a","b","c"]
    start=time.time()
    task_pool=threadpool.ThreadPool(5)
    requests=threadpool.makeRequests(sayhello,seed)
    for req in requests:
        task_pool.putRequest(req)
    task_pool.wait()
    end=time.time()
    time_m = end-start
    print("time: "+str(time_m))
    start1=time.time()
    for each in seed:
        sayhello(each)
    end1=time.time()
    print("time1: "+str(end1-start1))

if __name__ == '__main__':
    main(）

方法二：使用concurrent.futures模块

from concurrent.futures import ThreadPoolExecutor
import time

import time
from concurrent.futures import ThreadPoolExecutor, wait, as_completed

ll = []
def sayhello(a):
    print("hello: "+a)
    ll.append(a)
    time.sleep(0.8)

def main():
    seed=["a","b","c","e","f","g","h"]
    start1=time.time()
    for each in seed:
        sayhello(each)
    end1=time.time()
    print("time1: "+str(end1-start1))
    start2=time.time()
    with ThreadPoolExecutor(2) as executor:
        for each in seed:
            executor.submit(sayhello,each)
    end2=time.time()
    print("time2: "+str(end2-start2))

def main2():
    seed = ["a", "b", "c", "e", "f", "g", "h"]
    executor = ThreadPoolExecutor(max_workers=10)
    f_list = []
    for each in seed:
        future = executor.submit(sayhello, each)
        f_list.append(future)
    wait(f_list)
    print(ll)
    print('主线程结束')


def main3():
    seed = ["a", "b", "c", "e", "f", "g", "h"]
    with ThreadPoolExecutor(max_workers=2) as executor:
        f_list = []
        for each in seed:
            future = executor.submit(sayhello, each)
            f_list.append(future)
        wait(f_list,return_when='ALL_COMPLETED')
        print(ll)
        print('主线程结束')

if __name__ == '__main__':
    main3()

方法三：使用vthread模块

参考：https://pypi.org/project/vthr...

demo1

import vthread
 
@vthread.pool(6)
def some(a,b,c):
    import time;time.sleep(1)
    print(a+b+c)
 
for i in range(10):
    some(i,i,i)

demo2:分组线程池

import vthread
pool_1 = vthread.pool(5,gqueue=1) # open a threadpool with 5 threads named 1
pool_2 = vthread.pool(2,gqueue=2) # open a threadpool with 2 threads named 2

@pool_1
def foolfunc1(num):
    time.sleep(1)
    print(f"foolstring1, test3 foolnumb1:{num}")

@pool_2
def foolfunc2(num):
    time.sleep(1)
    print(f"foolstring2, test3 foolnumb2:{num}")

@pool_2
def foolfunc3(num):
    time.sleep(1)
    print(f"foolstring3, test3 foolnumb3:{num}")

for i in range(10): foolfunc1(i)
for i in range(4): foolfunc2(i)
for i in range(2): foolfunc3(i)

来源：https://segmentfault.com/a/1190000017324613